Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions - Practice and Problem-Solving Exercises - Page 556: 11

Answer

Axis of Symmetry =$\gt$ $x=\frac{3}{2}$ Vertex =$\gt$ $(\frac{3}{2}, \frac{19}{4})$

Work Step by Step

Axis of symmetry: $x=\frac{-(-b)}{2a}$ $x=\frac{-(-9)}{2(3)}$ $x=\frac{9}{6} \approx \frac{3}{2}$ Vertex: $y = 3x^{2}-9x+2$ *Plug in the axis of symmetry in place of x* $y = 3(\frac{3}{2})^2-9( \frac{3}{2}) + 2$ $y = 3(\frac{9}{4})-\frac{27}{2}+ 2$ $y = \frac{27}{4}-\frac{27}{2} + 2$ $y =-\frac{19}{4} $
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