Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 538: 68

Answer

$(w+12)^{2}$

Work Step by Step

$w^{2}+24w+144=$ ...write last term as a square. $=w^{2}+24w+12^{2}$ ...does middle term equal $2ab$? $24w=2(w)(12)$ yes. $=w^{2}+2(w)(12)+12^{2}$ ...write as the square of a binomial. $=(w+12)^{2}$
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