Answer
$(3z-4)(3z+4)$
Work Step by Step
$9z^{2}-16=$
...write each term as a square.
$=(3z)^{2}-4^{2}$
...factor using the rule for a difference of two squares.
($a^{2}-b^{2})=(a+b)(a-b),\qquad a=3z,\ b=4$)
$=(3z-4)(3z+4)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - Chapter Review - Page 538: 62
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