Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 538: 64

Answer

$(7n-2)(7n+2)$

Work Step by Step

$49n^{2}-4=$ ...write each term as a square. $=(7n)^{2}-2^{2}$ ...factor using the rule for a difference of two squares. ($a^{2}-b^{2})=(a+b)(a-b),\ \quad a=7n,\ b=2$) $=(7n-2)(7n+2)$
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