Answer
$8(m^{2}+5)(m+4)$
Work Step by Step
$8m^{3}+32m^{2}+40m+160=$
...factor out the GCF.
$=8(m^{3}+4m^{2}+5m+20)$
...factor by grouping.
$=8[m^{2}(m+4)+5(m+4)]$
...factor again.
$=8(m^{2}+5)(m+4)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 33
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