Answer
$g(5g^{2}+20)(g-1)$
Work Step by Step
$5g^{4}-5g^{3}+20g^{2}-20g=$
...factor out the GCF.
$=g(5g^{3}-5g^{2}+20g-20)$
...factor by grouping.
$=g[5g^{2}(g-1)+20(g-1)]$
...factor again.
$=g(5g^{2}+20)(g-1)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 24
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