Answer
$2(d^2+4)(2d-3)$
Work Step by Step
$4d^3-6d^2+16d-24$
Factor out the GCF
$=4d(d^2+4)-6(d^2+4)$
Factor by grouping
$=(d^2+4)(4d-6)$
$=2(d^2+4)(2d-3)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 27
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