Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 528: 67

Answer

$4h^{2}$

Work Step by Step

$16h^{4}-12h^{3}-36h^{2}$ ... factor each term. $16h^{4}=(2\cdot 2)\cdot 2\cdot 2\cdot(h\cdot h)\cdot h\cdot h$ $12h^{3}=(2\cdot 2)\cdot 3\cdot(h\cdot h)\cdot h$ $36h^{2}=(2\cdot 2)\cdot 2\cdot 2\cdot 2\cdot(h\cdot h)$ GCF: $4h^{2}$
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