Answer
$ (x^{10}-2y^{5})^{2}$
Work Step by Step
$x^{20}-4x^{10}y^{5}+4y^{10}=$
...recognize a square of a binomial.
...($a=x^{10},\ b=2y^{5},\ \quad $test the middle term: $2ab=2(x^{10})(2y^{5})=4x^{10}y^{5}$)
$=(x^{10}-2y^{5})^{2}$
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