Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 528: 54

Answer

$3(6n^{3}-7)(6n^{3}-7)$

Work Step by Step

$108n^{6}-147=$ ...factor out the GCF, $3$. $=3(36n^{6}-49)$ ...write the expression in the parentheses as the difference of two squares. ...($a=6n^{3},b=7$) $=3(6n^{3}-7)(6n^{3}-7)$
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