Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Lesson Check - Page 526: 7

Answer

The difference of two squares.$\qquad(3h+8)(3h-8)$

Work Step by Step

$9h^{2}-64=$ ...write each term as a square. $=(3h)^{2}-8^{2}$ ...factor using the rule for a difference of two squares. $a^{2}-b^{2}=(a+b)(a-b),\qquad a=3h,\ b=8$ $=(3h+8)(3h-8)$ The difference of two squares.$\qquad(3h+8)(3h-8)$
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