Answer
$(y-8)^{2}$
Work Step by Step
$y^{2}-16y+64=$
...write the last term as a square.
$=y^{2}-16y+8^{2}$
...does middle term equal $2ab$?
$16y=2(y)(8)$
$=y^{2}-2(y)(8)+8^{2}$
...write as the square of a binomial.
$=(y-8)^{2}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Lesson Check - Page 526: 1
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