Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Lesson Check - Page 526: 2

Answer

$(3q+2)^{2}$

Work Step by Step

$9q^{2}+12q+4=$ ...write first and last terms as squares. $=(3q)^{2}+12q+(2)^{2}$ ...does middle term equal $2ab$? $12q=2\cdot(3q)\cdot(2)$ $=(3q)^{2}+2\cdot(3q)\cdot(2)+(2)^{2}$ ...write as the square of a binomial. $=(3q+2)^{2}$
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