Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Practice and Problem-Solving Exercises - Page 509: 69

Answer

$6x(2x^{3}+5x^{2}+7)$

Work Step by Step

List the factors of each term, note the common factors: $12x^{4}=2\cdot(2\cdot 3)\cdot(x)\cdot x\cdot x\cdot x$ $30x^{3}=(2\cdot 3)\cdot 5\cdot(x)\cdot x\cdot x$ $42x=(2\cdot 3)\cdot 7\cdot(x)$ GCF=$(2\cdot 3)\cdot(x)$, or $6x$. $12x^{4}+30x^{3}+42x$= ...factor out the GCF from each term. $=6x(2x^{3})+6x(5x^{2})+6x(7)$ ...apply the Distributive Property. =$6x(2x^{3}+5x^{2}+7)$
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