Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Practice and Problem-Solving Exercises - Page 509: 56

Answer

$a^{2}+b^{2}+c^{2}+2ab+2bc+2ac$

Work Step by Step

Addition is associative, we can write $a+b+c$ as a sum of two terms: $(a+b+c)^{2}=[(a+b)+c]^{2}$ ... and we now square the binomial $=(a+b)^{2}+2(a+b)(c)+c^{2}$ ... square the binomial, distribute $2c(a+b)$... $=a^{2}+2ab+b^{2}+2ac+2bc+c^{2}$ ... simplify =$a^{2}+b^{2}+c^{2}+2ab+2bc+2ac$
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