Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Practice and Problem-Solving Exercises - Page 509: 62

Answer

$6x^{2}-11x-10$

Work Step by Step

$(3x+2)(2x-5)=$ $...$distribute the second factor, $(2x-5)$. $=3x(2x-5)+2(2x-5)\qquad$...distribute $3x$. $=6x^{2}-15x+2(2x-5)\qquad$ ...distribute $2$. $=6x^{2}-15x+4x-10\qquad$ ...gather like terms. =$6x^{2}-11x-10$
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