Answer
$(\frac{q^2}{p})^2$
Work Step by Step
We are given:
$\frac{1}{p^2q^{-4}r^0}$
$=\frac{q^4}{p^2}$
$=(\frac{q^2}{p})^2$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 475: 9
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