Answer
$(\frac{2y^4}{x})^2$
Work Step by Step
We are given:
$\frac{4x^{-2}}{y^{-8}}$
$=\frac{4y^8}{x^2}$
$=(\frac{2y^4}{x})^2$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 475: 8
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