Answer
$b^{31}$
Work Step by Step
You have ($\frac{b^4{^/}{^5}}{b^7}$$)^{-5}$.Simplify the expression:
($\frac{1}{b{^3}{^1}{^/}{^5}}$$)^{-5}$ -subtract the exponents on B-
($\frac{b{^3}{^1}{^/}{^5}}{1}$$)^{5}$ -apply exponent rule ($\frac{a}{b}$$)^{-c}$=($\frac{b}{a}$$)^{c}$-
$b^{{\frac{31}{5}} {\times} 5}$ -apply exponent rule ($a^{b}$$)^{c}$=$a^{bc}$
$\frac{31}{5}$ $\times$ 5=31
=$b^{31}$
