Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 443: 38

Answer

$\frac{1}{32}$

Work Step by Step

You have ($\frac{2^2}{2^3}$$)^{5}$.Simplify: ($\frac{2^2}{2^3}$)=$\frac{1}{2}$ -divide then subtract the exponents- ($\frac{1}{2}$$)^{5}$ -apply exponent rule ($\frac{a}{b}$$)^{c}$=$\frac{a^c}{b^c}$- $\frac{1^5}{2^5}$ -do the exponents- =$\frac{1}{32}$
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