Answer
$\frac{1}{8n^3}$
Work Step by Step
You have ($\frac{2n^2{^-}{^1}}{1}$$)^{-3}$ after using the quotient of powers property. Simplify the expression:
(2$n^{2-1}$$)^{-3}$ -Apply rule $\frac{a}{1}$=a-
(2n$)^{-3}$ -Apply $n^{2-1}$=n-
$\frac{1}{2n^3}$ -apply rule $a^{-b}$=$\frac{1}{a^b }$
$\frac{1}{2^3n^3}$ -apply rule (a $\times$ b$)^{n}$=$a^{n}$$b^{n}$
Simplify the exponents:
=$\frac{1}{8n^3}$
