Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 442: 18

$c^{1/2}$ $\times$$d^{-4}$

You have $\frac{c^2{^/}{^3}d^-{^5}}{c^1{^/}{^6}d^-{^1}}$.Solve: $\frac{c^2{^/}{^3}d^-{^5}}{c^1{^/}{^6}d^-{^1}}$ -apply exponent rule $\frac{x^a}{x^b}$=$x^{a-b}$- $c^{2/3-1/6}$ $\times$ $d^{-5-(-1)}$ -subtract- =$c^{1/2}$ $\times$$d^{-4}$