Answer
$\frac{1}{d^3}$
Work Step by Step
You have $\frac{d^1{^4}}{d^1{^7}}$.Solve:
$\frac{d^1{^4}}{d^1{^7}}$ -apply exponent rule $\frac{x^a}{x^b}$=$\frac{1}{x^b{^-}{^a}}$
$\frac{1}{d^1{^7}{^-}{^1}{^4}}$
=$\frac{1}{d^3}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 442: 14
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