Answer
$n^{3}$
Work Step by Step
You have $\frac{n^-{^1}}{n^-{^4}}$.Solve:
$\frac{n^-{^1}}{n^-{^4}}$ -apply exponent rule $\frac{x^a}{x^b}$=$x^{a-b}$.
$n^{-1-(-4)}$
=$n^{3}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 442: 15
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