Answer
$({3x^{3}y^{0})^{3} = 27x^{9}}$
Work Step by Step
When we raise a power to a power, we multiply the powers together and keep the base. If the bases of two exponential terms are the same, then the exponents are equal to one another.
First, we need to understand that on the right side of the equation, there is no $y$ term present. This means that the $y$ term actually equals $1$.
$y^0=1$
$3n = 0$
Divide both sides by $3$ to solve:
$n = 0$
Let's rewrite the equation:
$({3x^{3}y^{0})^{3} = 27x^{9}}$
