Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-3 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 437: 25

Answer

$\frac{1}{6g^2}$

Work Step by Step

You are given: $36^{-1/2}$ $g^{4*-1/2}$.Simplify the expression: $\frac{1}{6}$$g^{-2}$ -distribute -$\frac{1}{2}$ by multiplying existing exponents.- $g^{-2}$=$\frac{1}{g^2}$ -Use the exponent rule $x^{-y}$=$\frac{1}{g^2}$- The simplified expression is $\frac{1}{g^2}$
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