Answer
$9a^{6}$$b^{8}$
Work Step by Step
\ltYou are given ($3b^{-2}$$)^{2}$ ($a^{2}$$b^{4}$$)^{3}$.You have to simplify the expression:
($3^{2}$($b^{-2}$$)^{2}$) (($a^{2}$$)^{3}$($b^{4}$$)^{3}$) -Raise each term in the parentheses to the power outside of it-
(9$b^{-4}$)($a^{6}$$b^{12}$) -simplify the exponents-
9$a^{6}$$b^{-4+12}$ -add the exponents with the same base since you are multiplying-
The simplified expression is $9a^{6}$$b^{8}$
