Answer
$ t^{(-14)}$
Work Step by Step
$(t^2)^{(-2)} \times (t^2)^{(-5)}$
When solving for the power of a power, we have to multiply the exponents.
Solving, we get:
$t^{(2\times-2)}\times t^{(2\times-5)}$ =
$t^{(-4)} \times t ^{(-10)} = t^{(-4-10)}= t^{-14}$