Answer
$c^\frac{1}{3}$
Work Step by Step
$(c^3)^\frac{1}{9}$ $\times$ $(d^3)^0$
You have to multiply exponents when raising a power to a power. So we get:
$c^{(3\times\frac{1}{9})}$$\times$ $d^{(3\times0)}$ =$c^\frac{3}{9}$$\times$ $d^0$ =$c^\frac{1}{3}$ $\times 1$ = $c^\frac{1}{3}$