Answer
$d^{19}$
Work Step by Step
You have d($d^{-2}$$)^{-9}$.Solve the exponents:$(d^{-2}$$)^{-9}$=$d^{18}$.You now have:
$d^{18}$(d$)^{1}$ -apply exponent rule:$a^{b}$ $\times$ $a^{c}$=$a^{b+c}$-
$d^{1+18}$
=$d^{19}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-3 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 436: 16
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