Answer
The answer is $\frac{4}{x^{5}r^{2}ny^{2}}$
Work Step by Step
To solve this expression, we need to multiply instead of dividing:
= $\frac{2x^{-5}y^{3}}{n^{2}}$ $\div$ $\frac{r^{2}y^{5}}{2n}$
= $\frac{2y^{3}}{x^{5}n^{2}}$ $\times$ $\frac{2n}{r^{2}y^{5}}$
= $\frac{4}{x^{5}r^{2}n^{2-1}y^{5-3}}$
= $\frac{4}{x^{5}r^{2}ny^{2}}$
