Answer
The solution to this system is x=0, and the ordered pair where this occurs is (0,-1.5).
Work Step by Step
To start this problem, we must first rearrange $2x-y = 1.5$ into a form that we can plug into the calculator. By adding a y to both sides we can cancel out the one on the left and remain with one on the right side. Subtracting 1.5 from both sides will then get y alone, which is the form we need it. This new equation becomes $ y= 2x-1.5 $.
Using a table, we first map both equations ($ y= 2x-1.5 $ and $ y= \frac{1}{2}x-1.5 $) into the y=field on the graphing calculator. Using the standard tblset start of 0 and ending at 1, we can then view the table using the TABLE function. Once the table generates, we can observe that the only point of x where both equations are equal is 0. This shows that, according to the table, 0 is a solution to this system.
Using a graph, we also map both equations ($ y= 2x-1.5 $ and $ y= \frac{1}{2}x-1.5 $) into the y=field on the graphing calculator. We then use the CALC (2nd + TRACE) function and then the intersect function. This will allow for us to see where on the graph these two equations intersect, which will show us the solution. After navigating to intersect and selecting a point on either graph, the calculator returns an intersect value of (0,-1.5). This shows that the solution to this system is at x=0. Attached is a sketch of this graph.
