Answer
0
Work Step by Step
You do not replace the coins, so the events are dependent.
1 of the 9 coins is a nickel:
P(nickel)=$\frac{1}{9}$
0 of the 8 remaining coins is a nickel:
P(nickel after nickel)=$\frac{0}{8}$=0
P(nickel then nickel)=P(nickel) $\times$ P(nickel after nickel)
P(nickel then nickel)=$\frac{1}{9}$ $\times$ 0
P(nickel then nickel)=0
