Answer
$\frac{1}{12}$
Work Step by Step
You do not replace the coins, so the events are dependent.
3 of the 9 coins are dimes:
P(dime)=$\frac{3}{9}$=$\frac{1}{3}$
2 of the 8 remaining coins are a penny:
P(penny after dime)=$\frac{2}{8}$=$\frac{1}{4}$
P(dime then penny)=P(dime) $\times$ P(penny after dime)
P(dime then penny)=$\frac{1}{3}$ $\times$ $\frac{1}{4}$
P(dime then penny)=$\frac{1}{12}$
