Answer
$\frac{1}{12}$
Work Step by Step
You do not replace the coins, so the events are dependent.
2 of the 9 coins are pennies:
P(penny)=$\frac{2}{9}$
3 of the 8 remaining coins are dimes:
P(dime after penny)=$\frac{3}{8}$
P(penny then dime)=P(penny) $\times$ P(dime after penny)
P(penny then dime)=$\frac{2}{9}$ $\times$ $\frac{3}{8}$
P(penny then dime)=$\frac{1}{12}$
