Answer
9
Work Step by Step
We know that:
$_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$
$_9C_1 = \frac{9!}{(9-1)!1!}$
$\frac{ 9!}{8!}$
We also know that:
$x! = x(x-1)(x-2)...(1)$
Thus, we have:
9
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 12 - Data Analysis and Probability - 12-7 Theoretical and Experimental Probability - Practice and Problem-Solving Exercises - Page 774: 53
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