Answer
6
Work Step by Step
We know that:
$_nP_r = \frac{n!}{(n-r)!}$
$_3P_3 = \frac{3!}{(3-3)!}$
$\frac{3!}{0!}= 3!$
We also know that:
$x! = x(x-1)(x-2)...(1)$
Thus, we have:
6
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