Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 767: 52

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Use the formula of permutation: $_{n}$P$_{r}$=$\frac{n!}{(n-r)!}$. Plug in 4 for N and 3 for R: $_{n}$P$_{r}$=$\frac{n!}{(n-r)!}$ $_{4}$P$_{3}$=$\frac{4!}{(4-3)!}$ -simplify- $_{4}$P$_{3}$=$\frac{4!}{1!}$ -write using factorial- $_{4}$P$_{3}$=$\frac{4*3*2*1}{1}$ -simplify- $_{4}$P$_{3}$=24