Answer
$\frac{7b^2+6b-4}{3b(b+2)}$
Work Step by Step
$\frac{4b-2}{3b}+\frac{b}{b+2}$
Add:
$=\frac{(4b-2)(b+2)+3b(b)}{3b(b+2)}$
$=\frac{4b^2+8b-2b-4+3b^2}{3b(b+2)}$
Simplify:
$=\frac{7b^2+6b-4}{3b(b+2)}$
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