Answer
$9a^2b^4$.
Work Step by Step
We are given:
$=\frac{4}{a^2b^3},\frac{3}{9ab^4}$
The denominators are $a^2b^3,9ab^4$.
The common factors are $ab^3$.
Hence, the LCD is $9a^2b^4$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - Chapter Test - Page 719: 15
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