Answer
The answer is $2x^3-2x^2-2x-2-\frac{2}{2x-1}$
Work Step by Step
$(4x^4-6x^3-2x^2-2x) \div (2x-1)$
$2x^3$
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$2x-1) 4x^4-6x^3-2x^2-2x$
$-4x^4+2x^3$
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$-4x^3-2x^2 -2x$
$4x^3-2x^2$
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$-4x^2-2x$
$4x^2 -2x$
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$-4x$
$4x-2$
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$-2$
The answer is $2x^3-2x^2-2x-2-\frac{2}{2x-1}$