Answer
$=n+2$
Work Step by Step
$\frac{n^2+7n-8}{n-1}.\frac{n^2-4}{n^2+6n-16}$
$=\frac{(n-1)(n+8)}{n-1}.\frac{(n-2)(n+2)}{(n-2)(n+8)}$
$=n+2$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 683: 64
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