Answer
$2a^2b^2-3ab^3+5ab^2$
Work Step by Step
$(4a^3b^4-6a^2b^5+10a^2b^4) \div 2ab^2$
$=\frac{4a^3b^4}{2ab^2}-\frac{6a^2b^5}{2ab^2}+\frac{10a^2b^4}{2ab^2}$
$=2a^2b^2-3ab^3+5ab^2$
The answer is $2a^2b^2-3ab^3+5ab^2$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 683: 56
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