Answer
The answer is $2b^3-2b^2+3$.
Work Step by Step
$(2b^6+2b^5-4b^4+b^3+8b^2-3) \div (b^3+2b^2-1)$
$2b^3-2b^2+3$
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$b^3+2b^2-1) 2b^6+2b^5-4b^4+b^3+8b^2-3$
$-2b^6-4b^5+2b^3$
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$-2b^5-4b^4+3b^3+8b^2$
$2b^5+4b^4-2b^2$
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$3b^3+6b^2-3$
$-3b^3-6b^2+3$
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$0$
The answer is $2b^3-2b^2+3$.