Answer
$=\frac{(a-2)^2}{3a}$
Work Step by Step
$\frac{a^2+2a-8}{\frac{3a}{\frac{a+4}{a-2}}}$
$=\frac{(a-2)(a+4)}{3a}\times\frac{a-2}{a+4}$
$=\frac{a-2}{3a}\times\frac{a-2}{1}$
$=\frac{(a-2)^2}{3a}$
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