Answer
$ 3k^{2}(k+1)$
Work Step by Step
This becomes : $\frac{k^{2}+k}{5k} \times \frac{15k^{2}}{1}$
$= \frac{k(k+1)}{5k} \times \frac{15k^{2}}{1}$
$= \frac{k(k+1)}{1} \times \frac{3k}{1}$
$= 3k^{2}(k+1)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Lesson Check - Page 673: 3
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