Answer
$\frac{4x}{(x+7)(2x+3)}$
Work Step by Step
$\frac{8x^2-12x}{x+7} \div(4x^2-9)$
$=\frac{8x^2-12x}{x+7} \times \frac{1}{4x^2-9}$
$=\frac{4x(2x-3)}{x+7}\times\frac{1}{(2x-3)(2x+3)}$
$=\frac{4x}{x+7}\times\frac{1}{2x+3}$
$=\frac{4x}{(x+7)(2x+3)}$
