Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 4

Answer

b=24

Work Step by Step

A=10,C=26.Find B: $a^{2}$+$b^{2}$=$c^{2}$ $10^{2}$+$b^{2}$=$26^{2}$ 100+$b^{2}$=676 $b^{2}$=576 $\sqrt b{^2}$=$\sqrt {576}$ b=24
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