Answer
$\frac{2\sqrt 6+3}{5}$
Work Step by Step
We are given:
$\frac{\sqrt 6}{4-\sqrt 6}$
Multiplying the equation with $\frac{4+\sqrt 6}{4+\sqrt 6}$
$=\frac{\sqrt 6(4+\sqrt 6)}{16-6}$
$=\frac{4\sqrt 6+6}{10}$
$=\frac{2\sqrt 6+3}{5}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 13
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