Answer
$\frac{1}{7}(3\sqrt2-2)$
Work Step by Step
We are given:
$\frac{\sqrt 2}{\sqrt 2+3}$
Multiplying the equation with $\frac{\sqrt2-3}{\sqrt2-3}$
$=\frac{\sqrt 2(\sqrt2-3)}{2-9}$
$=\frac{2-3\sqrt 2}{-7}$
$=\frac{1}{7}(3\sqrt2-2)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 14
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